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JEE Main 20163 April
Exam
JEE Main
Year
2016
Date
3 April
Subject
Physics
Chapter
Semiconductors

JEE Main 2016 · 3 April · Physics · Semiconductors

For a common emitter configuration, if α and β have their usual...

For a common emitter configuration, if α\alpha and β\beta have their usual meanings, the correct relationship between α\alpha and β\beta is:

Options

  1. Aα = \dfrac{β}{1 + β}
  2. Bα=β21+β2\alpha = \dfrac{{\beta}^{2}}{1 + {\beta}^{2}}
  3. C1α=1β−1\dfrac{1}{\alpha} = \dfrac{1}{\beta} - 1
  4. Dα = \dfrac{β}{1 - β}

Correct answer

A. α = \dfrac{β}{1 + β}

Step-by-step solution

IE=IC+IB{I}_{E} = {I}_{C} + {I}_{B}

IEIC=1+IBIC\dfrac{{I}_{E}}{{I}_{C}} = 1 + \dfrac{{I}_{B}}{{I}_{C}}

1∝=1+1β\dfrac{1}{∝} = 1 + \dfrac{1}{\beta}

1∝=β+1β\dfrac{1}{∝} = \dfrac{\beta + 1}{\beta}

∝=β1+β∝ = \dfrac{\beta}{1 + \beta}

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