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For a common emitter configuration, if α and β have their usual meanings, the correct relationship between α and β is:

Options

  1. Aα = β 1 + β
  2. Bα = β 2 1 + β 2
  3. C1 α = 1 β - 1
  4. Dα = β 1 - β

Correct answer

A. α = β 1 + β

Step-by-step solution

I E = I C + I B I E I C = 1 + I B I C 1 ∝ = 1 + 1 β 1 ∝ = β + 1 β ∝ = β 1 + β

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