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JEE Main 201511 AprilOnline
Exam
JEE Main
Year
2015
Date
11 April
Mode
Online
Subject
Physics
Chapter
Semiconductors

JEE Main 2015 · 11 April · Online · Physics · Semiconductors

The value of the resistor, R _ S , needed in the DC voltage...

The value of the resistor, RS{R}_{S}, needed in the DC voltage regulator circuit shown here, equals:

The value of the resistor, R _ S , needed in the DC voltage regulator circuit shown here, equals:

Options

  1. A\dfrac{\left({V}_{i} + {V}_{L}\right)}{\left(n + 1\right){I}_{L}}
  2. B\dfrac{\left({V}_{i} - {V}_{L}\right)}{n{I}_{L}}
  3. C\dfrac{\left({V}_{i} + {V}_{L}\right)}{n{I}_{L}}
  4. D\dfrac{\left({V}_{i} - {V}_{L}\right)}{\left(n + 1\right){I}_{L}}

Correct answer

D. \dfrac{\left({V}_{i} - {V}_{L}\right)}{\left(n + 1\right){I}_{L}}

Step-by-step solution

The value of the resistor, R _ S , needed in the DC voltage regulator circuit shown here, equals:

Across zener diode VL=constant{V}_{L} = constant

∵Vi=VL+(n+1)ILRS∵ {V}_{i} = {V}_{L} + \left(n + 1\right){I}_{L}{R}_{S}

⇒Vi−VL=(n+1)ILRS⇒ {V}_{i} - {V}_{L} = \left(n + 1\right){I}_{L}{R}_{S}

⇒RS=Vi−VL(n+1)IL⇒ {R}_{S} = \dfrac{{V}_{i} - {V}_{L}}{\left(n + 1\right){I}_{L}}
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