JEE Main2014PhysicsSemiconductorsActual
Identify the gate and match A , B , Y in the bracket to check.
Options
- AO R   ( A = 1 ,   B = 1 ,   Y = 0 )
- BX O R   ( A = 0 ,   B = 0 ,   Y = 0 )
- CN O T   ( A = 1 ,   B = 1 ,   Y = 1 )
- DA N D   ( A = 1 ,   B = 1 ,   Y = 1 )
Correct answer
D. A N D   ( A = 1 ,   B = 1 ,   Y = 1 )
Step-by-step solution
The output of the first NAND gate Y ' = A · B ¯ The output of the second NAND gate Y = A · B ¯ · A · B ¯ ¯ ⇒   Y = A · B ¯ ¯ + A · B ¯ ¯ ⇒   Y = A · B So, the equivalent circuit will be an AND gate. A N D   ( A = 1 ,   B = 1 ,   Y = 1 )