Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of $20 \Omega$ and infinite backward resistance. Resistors $\mathrm{R}_1=\mathrm{R}_2=\mathrm{R}_3=50 \Omega$ . Battery voltage is $6 \mathrm{~V}$ . The current through $\mathrm{R}_3$ is :

Question

Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of

20 \Omega

and infinite backward resistance. Resistors

\mathrm{R}_1=\mathrm{R}_2=\mathrm{R}_3=50 \Omega

. Battery voltage is

6 \mathrm{~V}

. The current through

\mathrm{R}_3

is :

Quantrex Academy · Accepted Answer

Correct answer: A. 50 ~mA

Here, diodes D_1 and D_2 are forward biased and D_3 is reverse biased. Therefore current through R_3i= V R^ =(6)/(120)=(1)/(20) ~A= 50 ~mA

Figure shows a circuit in which three identical diodes are used....