100 mL of 0.1 M HA (weak acid) and 100 mL of 0.2 M NaA are mixed. What is the pH of resultant solution? ( K _ a of HA is 10⁻⁵ ; 2=0.3 )

Step-by-step solution

pH = pK _ a + [ Salt ] [ Acid ] aligned & pH =5+ [0.2] [0.1] [ pK _ a =- log K _ a =- log 10⁻⁵=5] . & pH =5+ 2 & pH =5+0.3 & pH =5.3 aligned