The pH of 0.01 M BOH solution is 10 . What is its degree of dissociation? (Given K _ b of BOH is 1 10⁻⁶ )

Step-by-step solution

aligned & BOH B ⁺+ OH ⁻ & K _ b = [ B ⁺ ] [ OH ⁻ ] [ BOH ] =1 10⁻⁶ & pH =10 pOH =14-10=4 & [ OH ⁻ ]=10⁻⁴ M . & Now, K _ b = Ca ^2 1- = [ OH ⁻ ] ^2 1- & K _ b [ OH ⁻ ] = ^2 1- ^2= 10⁻⁶ 10⁻⁴ =10⁻² & =10⁻¹ or 0.1 or 10 % aligned