At 25^ C , the solubility product of MCl is 1 10⁻¹⁰ . What is its molar solubility in 0.1 M NaCl solution at same temperature?

Step-by-step solution

K_ sp of M C l=1 10⁻¹⁰ . Let the molar solubility of MCl in 0.1 M NaCl be ' S ' mol L ⁻¹ . MCl M ⁺+ Cl ⁻ The concentration of Cl ⁻ will be (S+0.1) mol L ⁻¹ , as 0.1 ~mol ~L ⁻¹ are provided by 0.1 M NaCl . aligned & K_ sp = [M⁺ ] [ Cl ⁻ ] & K_ sp =S (S+0.1)=1 10⁻¹⁰ aligned As the K_ sp is very small, the S 0.1 and therefore can be ignored. S 0.1=1 10⁻¹⁰ S=10⁻⁹ ~mol ~L ⁻¹