1 ~L of 0.02 M aqueous HCl is mixed with 1 ~L of 0.01 M aqueous H ₂ SO ₄ solution. Assuming complete dissociation and no change in the volume upon mixing, the pH of resultant solution is ( ₁₀ 2=0.3 )

Step-by-step solution

Given, HCl 1 ~L 0.02 M H ₂ SO ₄ 1 ~L 0.01 M Moles of H ⁺ from HCl =1 0.02=0.02 Moles of H ⁺ from H ₂ SO ₄=1 0.01 2=0.02 Total moles in mixture =0.02+0.02=0.04 aligned [ H ⁺ ] & = Total moles Total volume & = 0.04 2 =0.02 pH & =- [ H ⁺ ]=- 0.02=1.7 aligned