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AP EAMCET202125 Aug 2021Evening ShiftChemistryIonic EquilibriumActual

If the molar solubility (in mol L ⁻¹ ) of a sparingly soluble salt A B₄ is S and the corresponding solubility product is K_ sp , then s in terms of K_ sp is given by the relation

Options

  1. AS= ( K_ sp 128 )^ 1 / 4
  2. BS= ( K_ sp 256 )^ 1 / 5
  3. CS= (256 K_ sp )^ 1 / 5
  4. DS= (128 K_ sp )^ 1 / 4

Correct answer

B. S= ( K_ sp 256 )^ 1 / 5

Step-by-step solution

For the reaction, array ccc A B₄(s) (a q) & A⁴⁺(a q)+4 B⁻(a q) - & S & 4 S array Molar solubility (in mol / L ) of a sparingly soluble salt A B₄ is ' S ' and corresponding solubility product is K_ sp . S in term of K_ sp is given by above relation is aligned & K_ sp = [A⁴⁺ ] [B⁻ ]^4 & K_ sp =S (4 S)^4 & K_ sp =256 S^5 aligned Hence, the molar solubility, S= ( K_ sp 256 )^ 1 5

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