JEE Main202628 January 2026Evening ShiftPhysicsUnits and DimensionsActual
Match List - I with List - II. ( array llll & List - I & & List - II A. & Coefficient of viscosity & I. & [M L⁻¹ T⁻¹] B. & Surface tension & II. & [M L⁰ T⁻²] C. & Pressure & III. & [M L⁻¹ T⁻²] D. & Surface energy & IV. & [M L² T⁻²] array ) Choose the correct answer from the options given below :
Options
- AA-I, B-II, C-IV, D-III
- BA-IV, B-I, C-II, D-III
- CA-I, B-II, C-III, D-IV
- DA-I, B-III, C-II, D-IV
Correct answer
C. A-I, B-II, C-III, D-IV
Step-by-step solution
(A) Coefficient of viscosity: = F dr A dv = [MLT⁻²][L] [L^2][LT⁻¹] = [ML⁻¹T⁻¹] → I (B) Surface tension: S = F L = [MLT⁻²] [L] = [MT⁻²] = [ML^0T⁻²] → II (C) Pressure: P = F A = [MLT⁻²] [L^2] = [ML⁻¹T⁻²] → III (D) Surface energy: E = S A = [MT⁻²][L^2] = [ML^2T⁻²] → IV Hence, A-I, B-II, C-III, D-IV.