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AP EAMCET202120 Aug 2021Morning ShiftChemistryIonic EquilibriumActual

The solubility of A g B r ( s ) , having solubility product 5 × 10 - 10 in 0 . 2 M NaBr solution, equals

Options

  1. A5 × 10 - 10 M
  2. B25 × 10 - 10 M
  3. C0 . 5   M
  4. D0 . 002   M

Correct answer

B. 25 × 10 - 10 M

Step-by-step solution

Here, the solubility product K sp of AgBr is 5 × 10 - 10   M . We know that for the reaction, AgBr   →   Ag + + Br - K sp   =   Ag + × Br - Also, it is given that the concentration of Br - is 0 . 2   M . Therefore, K sp   =   s Ag × s Br 5 × 10 - 10   =   s Ag × 0 . 2 ∴   s Ag   =   25 × 10 - 10

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