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JEE Main 20253 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
3 April
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2025 · 3 April · Evening Shift · Physics · Units and Dimensions

Match the LIST-I with LIST-II Choose the correct answer from the...

Match the LIST-I withLIST-IIMatch the LIST-I with LIST-II Choose the correct answer from the options given below :
Choose the correct answer from the options given below :

Options

  1. AA-III, B-IV, C-I, D-II
  2. BA-II, B-III, C-IV, D-I
  3. CA-III, B-II, C-I, D-IV
  4. DA-III, B-IV, C-II, D-I

Correct answer

A. A-III, B-IV, C-I, D-II

Step-by-step solution

(A) [k]=PVNT=ML2 T−2 K=ML2 T−2 K−1[\mathrm{k}]=\frac{\mathrm{PV}}{\mathrm{NT}}=\frac{\mathrm{ML}^2 \mathrm{~T}^{-2}}{\mathrm{~K}}=\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~K}^{-1}
(B) [η]=F6πrv=MLT−2 L2 T−1=ML−1 T−1[\eta]=\frac{\mathrm{F}}{6 \pi \mathrm{rv}}=\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}^2 \mathrm{~T}^{-1}}=\mathrm{ML}^{-1} \mathrm{~T}^{-1}
(C) [h]=Ef=ML2 T−2 T−1=ML2 T−1[\mathrm{h}]=\frac{\mathrm{E}}{\mathrm{f}}=\frac{\mathrm{ML}^2 \mathrm{~T}^{-2}}{\mathrm{~T}^{-1}}=\mathrm{ML}^2 \mathrm{~T}^{-1}
(D) dQdt=kAdTdx\frac{\mathrm{dQ}}{\mathrm{dt}}=\mathrm{k} \frac{\mathrm{AdT}}{\mathrm{dx}}
k=(ML2 T−3)LL2⋅ K=MLT−3 K−1\mathrm{k}=\frac{\left(\mathrm{ML}^2 \mathrm{~T}^{-3}\right) \mathrm{L}}{\mathrm{L}^2 \cdot \mathrm{~K}}=\mathrm{MLT}^{-3} \mathrm{~K}^{-1}
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