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JEE Main 20252 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
2 April
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2025 · 2 April · Evening Shift · Physics · Units and Dimensions

Match List-I with List-II. List-I List-II (A) Heat capacity of body...

Match List-I with List-II.
List-IList-II
(A) Heat capacity of body(I) J kg^{-1}
(B) Specific heat capacity of body(II) JK^{-1}
(C) Latent heat(III) J kg^{-1} K^{-1}
(D) Thermal conductivity(IV) Jm^{-1} K^{-1} s^{-1}

Choose the correct answer from the options given below :

Options

  1. A(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  2. B(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  3. C(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. D(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct answer

D. (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Step-by-step solution

C′=ΔQΔT=JK−1 S=ΔQmΔT=Jkg−1 K−1 L=ΔQm=Jkg−1ΔQ=KAΔTL⇒K=ΔQ(L)AΔT=Jm−1 K−1 s−1\begin{aligned} & \mathrm{C}^{\prime}=\frac{\Delta \mathrm{Q}}{\Delta \mathrm{T}}=\mathrm{JK}^{-1} \\ & \mathrm{~S}=\frac{\Delta \mathrm{Q}}{\mathrm{m} \Delta \mathrm{T}}=\mathrm{Jkg}^{-1} \mathrm{~K}^{-1} \\ & \mathrm{~L}=\frac{\Delta \mathrm{Q}}{\mathrm{m}}=\mathrm{Jkg}^{-1} \\ & \Delta \mathrm{Q}=\frac{\mathrm{KA} \Delta \mathrm{T}}{\mathrm{L}} \Rightarrow \mathrm{K}=\frac{\Delta \mathrm{Q}(\mathrm{L})}{\mathrm{A} \Delta \mathrm{T}}=\mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1}\end{aligned}
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