JEE Main202529 Jan 2025Evening ShiftPhysicsUnits and DimensionsActual
Match List - I with List - II. Choose the correct answer from the options given below :
Options
- A(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
- B(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
- C(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Correct answer
C. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
Step-by-step solution
(A) [ Y ]= F A ( ) MLT ⁻² ~L ^2 = ML ⁻¹ ~T ⁻² (B) Torque ( )= r F ( )= L MLT ⁻²= ML ^2 ~T ⁻²( IV ) (C) Coefficient of viscosity F= A d V d t Pa sec [ ]= MLT ⁻² ~L ^2 T = ML ⁻¹ ~T ⁻¹ (D) Gravitational constant (G) aligned & F = GM ₁ M ₂ r ^2 & [ G ]= F r ^2 ~m ₁ ~m ₂ = MLT ⁻² L ^2 M ^2 = M ⁻¹ ~L ^3 ~T ⁻² aligned