JEE Main202430 Jan 2024Morning ShiftPhysicsUnits and DimensionsActual
Match List-I with List-II. List-I List-II A. Coefficient of viscosity I. ML 2 T - 2 B. Surface Tension II. ML 2 T - 1 C. Angular momentum III. ML - 1 T - 1 D. Rotational kinetic energy IV. ML 0 T - 2
Options
- AA-II, B-I, C-IV, D-III
- BA-I, B-II, C-III, D-IV
- CA-III, B-IV, C-II, D-I
- DA-IV, B-III, C-II, D-I
Correct answer
C. A-III, B-IV, C-II, D-I
Step-by-step solution
Viscous force is given by, F = η A d v d y . Hence, MLT - 2 = η L 2 T - 1 ⇒ η = ML - 1 T - 1 Surface tension is given by, S T = F ℓ . Hence, dimension will be = MLT - 2 [ L ] = ML 0 T - 2 Angular momentum, L = m v r = ML 2 T - 1 Rotational kinetic energy, K . E = 1 2 I ω 2 = ML 2 T - 2