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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2023 · 15 April · Morning Shift · Physics · Units and Dimensions

The speed of a wave produced in water is given by ν = λ ^ a g ^ b ρ...

The speed of a wave produced in water is given by ν=λagbρcν = {\lambda}^{a}{g}^{b}{ρ}^{c}. Where λ,g\lambda, g and ρρ are wavelength of wave, acceleration due to gravity and density of water respectively. The values of a,ba, b and cc respectively, are

Options

  1. A1,−1,01, - 1, 0
  2. B12,0,12\dfrac{1}{2}, 0, \dfrac{1}{2}
  3. C1,1,01, 1, 0
  4. D12,12,0\dfrac{1}{2}, \dfrac{1}{2}, 0

Correct answer

D. 12,12,0\dfrac{1}{2}, \dfrac{1}{2}, 0

Step-by-step solution

The dimensional form of velocity can be written as

[v]=\left[v\right] =\left[{\lambda}^{a}{g}^{b}{ρ}^{c}\right]

⇒[M0LT−1]⇒ \left[{M}^{0}L{T}^{- 1}\right] = {\left[L\right]}^{a}{\left[L{T}^{- 2}\right]}^{b}{\left[M{L}^{- 3}\right]}^{c}

Comparing the exponents for M,L,TM, L, T,

ForM,Mc=M0ForL,La+b−3c=L1ForT,T−2b=T−1ForM, {M}^{c} = {M}^{0}ForL, {L}^{a + b - 3c} = {L}^{1}ForT, {T}^{- 2b} = {T}^{- 1}

So,

c=0...(i)a+b−3c=1...(ii)−2b=−1...(iii)c = 0 . . . ( i ) a + b - 3c = 1 . . . ( ii ) - 2b = - 1 . . . ( iii )

From equations (i),(ii),(iii),

a=a =\dfrac{1}{2},b=, b =\dfrac{1}{2},c=0, c = 0

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