JEE Main 202325 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 25 January
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Units and Dimensions
JEE Main 2023 · 25 January · Evening Shift · Physics · Units and Dimensions
Match List I with List II List List II A Young's Modulus ( Y ) I [...
Match List I with List II
| List | List II | ||
| A | Young's Modulus | I | |
| B | Co-efficient of Viscosity | II | |
| C | Planck's Constant | III | |
| D | Work Function \left(ϕ\right)[ {ML}^{2}{T}^{– 2} ] |
Choose the correct answer from the options given below:
Options
- AA-II, B-III, C-IV, D-I
- BA-III, B-I, C-II, D-IV
- CA-I, B-III, C-IV, D-II
- DA-I, B-II, C-III, D-IV
Correct answer
B. A-III, B-I, C-II, D-IV
Step-by-step solution
(A) Young's modulus is stated as(B) Coefficient of viscosity is stated as , here, is velocity.
\left(η\right) = \dfrac{\left[{MLT}^{- 2}\right]}{\left[L\right]\left[{LT}^{- 1}\right]} = \left[{ML}^{- 1}{T}^{- 1}\right]h = \dfrac{\text{Energy}}{\text{Frequency}} = \dfrac{\left[{ML}^{2}{T}^{- 2}\right]}{\left[{T}^{- 1}\right]} = \left[{ML}^{2}{T}^{- 1}\right]
Thus, A-III, B-I, C-II, D-IV