JEE Main202325 Jan 2023Evening ShiftPhysicsUnits and DimensionsActual
Match List I with List II List List II A Young's Modulus ( Y ) I [ ML – 1 T – 1 ] B Co-efficient of Viscosity ( η ) II [ ML 2 T – 1 ] C Planck's Constant ( h ) III [ ML – 1 T – 2 ] D Work Function ϕ IV [ ML 2 T – 2 ] Choose the correct answer from the options given below:
Options
- AA-II, B-III, C-IV, D-I
- BA-III, B-I, C-II, D-IV
- CA-I, B-III, C-IV, D-II
- DA-I, B-II, C-III, D-IV
Correct answer
B. A-III, B-I, C-II, D-IV
Step-by-step solution
(A) Young's modulus is stated as Y = Stress Strain = F A ∆ l l = F l A ∆ l = MLT - 2 L L 2 L = ML - 1 T - 2 (B) Coefficient of viscosity is stated as η = F 6 π r v , here, v is velocity. η = MLT - 2 L LT - 1 = ML - 1 T - 1 (C) Planck's Constant is stated as h = Energy Frequency = ML 2 T - 2 T - 1 = ML 2 T - 1 (D) Work function has the same dimension as that of energy, so ϕ = ML 2 T - 2 Thus, A-III, B-I, C-II, D-IV