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JEE Main 202131 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
31 August
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2021 · 31 August · Evening Shift · Physics · Units and Dimensions

If velocity [V] time [T] and force [F] are chosen as the base...

If velocity [V]\left[V\right] time \left[T\right]andforce[F]and force \left[F\right] are chosen as the base quantities, the dimensions of the mass will be :

Options

  1. A[FVT−1]\left[FV{T}^{- 1}\right]
  2. B[FT−1V−1]\left[F{T}^{- 1}{V}^{- 1}\right]
  3. C[FT2V]\left[F{T}^{2}V\right]
  4. D[FTV−1]\left[FT{V}^{- 1}\right]

Correct answer

D. [FTV−1]\left[FT{V}^{- 1}\right]

Step-by-step solution

[M]1=[V]a[T]b[F]c[ M{]}^{1} = [ V{]}^{a} [ T{]}^{b} [ F{]}^{c}
[M]1=[LT−1]a[T]b[MLT−2]c[ M{]}^{1} = {\left[L{T}^{- 1}\right]}^{a} [ T{]}^{b}{\left[ML{T}^{- 2}\right]}^{c}
[M]1=[M]c[L]a+c[T]−a+b−2c[ M{]}^{1} = [ M{]}^{c} [ L{]}^{a + c} [ T{]}^{- a + b - 2c}
Thus,

{c=1,a+c=0andb−a−2c=0⇒a=−1⇒b=−1+2=1\begin{cases}c = 1, & a + c = 0\text{and} & b - a - 2c = 0 \\ ⇒ a = - 1 & ⇒ b = - 1 + 2 = 1\end{cases}
Thus, [M]=[V]−1[T]1[F]1[ M ] = [ V{]}^{- 1} [ T{]}^{1} [ F{]}^{1}

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