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JEE Main 202125 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
25 July
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2021 · 25 July · Evening Shift · Physics · Units and Dimensions

The force is given in terms of time t and displacement x by the...

The force is given in terms of time tt and displacement xx by the equation F=AcosBx+CsinDtF = AcosBx + CsinDt

The dimensional formula of ADB\dfrac{AD}{B} is:

Options

  1. A[M0LT−1]\left[{M}^{0}L{T}^{- 1}\right]
  2. B[ML2T−3]\left[{ML}^{2}{T}^{- 3}\right]
  3. C[M1L1T−2]\left[{M}^{1}{L}^{1}{T}^{- 2}\right]
  4. D[M2L2T−3]\left[{M}^{2}{L}^{2}{T}^{- 3}\right]

Correct answer

B. [ML2T−3]\left[{ML}^{2}{T}^{- 3}\right]

Step-by-step solution

[A]=[MLT−2][ A ] = \left[{MLT}^{- 2}\right]

[B]=[L−1][ B ] = \left[{L}^{- 1}\right]

[D]=[T−1][ D ] = \left[{T}^{- 1}\right]

\left[\dfrac{AD}{B}\right] = \dfrac{\left[{MLT}^{- 2}\right]\left[{T}^{- 1}\right]}{\left[{L}^{- 1}\right]}</p><p>[ADB]=[ML2T−3]</p><p>\left[\dfrac{AD}{B}\right] = \left[{ML}^{2}{T}^{- 3}\right]

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