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JEE Main 202126 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Morning Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2021 · 26 February · Morning Shift · Physics · Units and Dimensions

In a typical combustion engine the workdone by a gas molecule is...

In a typical combustion engine the workdone by a gas molecule is given by W=α2\betae−βx2kTW = {\alpha}^{2}\betae\dfrac{- \beta{x}^{2}}{kT}, where xx is the displacement, kk is the Boltzmann constant and TT is the temperature. If α\alpha and β\beta are constants, dimensions of α\alpha will be:

Options

  1. A[MLT−2]\left[{MLT}^{- 2}\right]
  2. B[M2LT−2]\left[{M}^{2}{LT}^{- 2}\right]
  3. C[MLT−1]\left[{MLT}^{- 1}\right]
  4. D[M0LT0]\left[{M}^{0}{LT}^{0}\right]

Correct answer

D. [M0LT0]\left[{M}^{0}{LT}^{0}\right]

Step-by-step solution

kTkT has dimension of energy

βx2kT\dfrac{\beta{x}^{2}}{kT} is dimensionless

\left[\beta\right]\left[{L}^{2}\right] = \left[{ML}^{2}{T}^{- 2}\right]

\left[\beta\right] = \left[{MT}^{- 2}\right]

α2βhasdimensionsof{\alpha}^{2}\beta has dimensions ofwork

\left[{\alpha}^{2}\right]\left[{MT}^{- 2}\right]=[ML2T−2]= \left[{ML}^{2}{T}^{- 2}\right]

\left[\alpha\right]=[M0LT0]= \left[{M}^{0}{LT}^{0}\right]

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