JEE Main202125 Feb 2021Morning ShiftPhysicsUnits and DimensionsActual
Match List - I with List - II : List - I List - II a h (Planck's constant) i MLT - 1 b E (kinetic energy) ii ML 2 T - 1 c V (electric potential) iii ML 2 T - 2 d P (linear momentum) iv ML 2 I - 1 T - 3 Choose the correct answer from the options given below:
Options
- Aa → ii , b → iii , c → iv , d → i
- Ba → i , b → ii , c → iv , d → iii
- Ca → iii , b → ii , c → iv , d → i
- Da → iii , b → iv , c → ii , d → i
Correct answer
A. a → ii , b → iii , c → iv , d → i
Step-by-step solution
By dimensional analysis. K . E . = ML 2   T - 2 P (linear momentum) = MLT - 1 h   ( planck's constant ) = ML 2   T - 1 V (electric potential ) = ML 2   T - 3 I - 1