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JEE Main 20203 SeptemberEvening Shift

Exam: JEE Main
Year: 2020
Date: 3 September
Shift: Evening Shift
Subject: Physics
Chapter: Units and Dimensions

JEE Main 2020 · 3 September · Evening Shift · Physics · Units and Dimensions

Amount of solar energy received on the earth's surface per unit...

Amount of solar energy received on the earth's surface per unit area per unit time is defined a solar constant. Dimension of solar constant is:

Options

A ${ML}^{2}{T}^{- 2}$
B ${ML}^{0}{T}^{- 3}$
C ${M}^{2}{L}^{0}{T}^{- 1}$
D ${MLT}^{- 2}$

Correct answer

B. ${ML}^{0}{T}^{- 3}$

Step-by-step solution

Solar constant $= \dfrac{Energy}{TimeArea}$

$= \dfrac{{M}^{1}{L}^{2}{T}^{- 2}}{{TL}^{2}} = {M}^{1}{L}^{0}{T}^{- 3}$

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