JEE Main20202 Sep 2020Morning ShiftPhysicsUnits and DimensionsActual
If speed V , area A and force F are chosen as fundamental units, then the dimension of Young's modulus will be :
Options
- AFA 2 V - 1
- BFA 2 V - 3
- CFA 2 V - 2
- DFA - 1 V 0
Correct answer
D. FA - 1 V 0
Step-by-step solution
Y ∝ F a V b A c    Y = F A M L T - 2 L 2 ∝ M 1 L 1 T - 2 a L 1 T - 1 b L 2 c M 1 L - 1 T - 2 ∝ M a La + b + 2 cT - 2 a - b a   +   b   +   2 c   =   – 1 – 2 a   +   b   =   – 2 a   =   1 ,   b   =   0 ,   c   =   – 1 Y = F 1 V 0 A - 1