If speed V , area A and force F are chosen as fundamental units,...

$Y ∝ {F}^{a}{V}^{b}{A}^{c}Y = \left(\dfrac{F}{A}\right)$

$\dfrac{ML{T}^{- 2}}{{L}^{2}} ∝ {\left({M}^{1}{L}^{1}{T}^{- 2}\right)}^{a}{\left({L}^{1}{T}^{- 1}\right)}^{b}{\left({L}^{2}\right)}^{c}$

${M}^{1}{L}^{- 1}{T}^{- 2} ∝ {M}^{a}{La}^{+}b + 2cT - 2a - b$

$a + b + 2c = – 1$

$– 2a + b = – 2$

$a = 1, b = 0, c = – 1$

$Y = {F}^{1}{V}^{0}{A}^{- 1}$