JEE Main 201911 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 11 January
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Units and Dimensions
JEE Main 2019 · 11 January · Morning Shift · Physics · Units and Dimensions
The force of interaction between two atoms is given by F=α β (- x^...
The force of interaction between two atoms is given by where is the distance, is the
Boltzmann constant and T is temperature and and are two constants. The dimensions of is:
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
Force of interaction between two atoms,
\therefore\left[\frac{\mathrm{x}^{2}}{\alpha \mathrm{k} \mathrm{T}}\right]=\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{0}
\Rightarrow \frac{\mathrm{L}^{2}}{[\alpha] \mathrm{ML}^{2} \mathrm{~T}^{-2}}=\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{0}
\Rightarrow[\alpha]=\mathrm{M}^{-1} \mathrm{~T}^{2}
[\mathrm{F}]=[\alpha][\beta]
\mathrm{MLT}^{-2}=\mathrm{M}^{-1} \mathrm{~T}^{2}[\beta]
\Rightarrow[\beta]=M^{2} L T^{-4}