Time (T) , velocity (C) and angular momentum (h) are chosen as...

M ∝ {T}^{x}{C}^{y}{h}^{z}$<br />${M}^{1}{L}^{0}{T}^{0} = {\left({T}^{1}\right)}^{x}{\left({L}^{1}{T}^{- 1}\right)}^{y}{\left({M}^{1}{L}^{2}{T}^{- 1}\right)}^{z}$<br />$[ {M}^{1}{L}^{0}{T}^{0} ] =[ {M}^{z}{L}^{y + 2z}{T}^{x - y - z} ]$]<br />$⟹ z = 1$<br />$y + 2z = 0, x - y - z = 0$<br />$solving$<br />$y = - 2$<br />and$x = - 1$<br />$M ⇒ \left[{T}^{- 1}{C}^{- 2}{h}^{1}\right]