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JEE Main 201226 MayOnline
Exam
JEE Main
Year
2012
Date
26 May
Mode
Online
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2012 · 26 May · Online · Physics · Units and Dimensions

The electrical resistance R of a conductor of length l and area of...

The electrical resistance RR of a conductor of length ll and area of cross section aa is given by R=ρlaR=\frac{\rho l}{a} where ' ρ\rho ' is the electrical resistivity. What is the dimensional formula for electrical conductivity ' σ\sigma ' which is reciprocal of resistivity?

Options

  1. A[M−1L−3T3A2]\left[M^{-1} L^{-3} T^3 A^2\right]
  2. B[ML−3T−3A2]\left[M L^{-3} T^{-3} A^2\right]
  3. C[ML3T−3A−2]\left[M L^3 T^{-3} A^{-2}\right]
  4. D[M−2L3T2A−1]\left[M^{-2} L^3 T^2 A^{-1}\right]

Correct answer

A. [M−1L−3T3A2]\left[M^{-1} L^{-3} T^3 A^2\right]

Step-by-step solution

Dimensional formula for electrical resistivity, ρ=[ML3 T−3 A−2]\rho=\left[\mathrm{ML}^3 \mathrm{~T}^{-3} \mathrm{~A}^{-2}\right] Dimensional formula for electrical conductivity, σ=1ρ\sigma=\frac{1}{\rho} is \left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^3 \mathrm{~A}^2\right]
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