50 mL of 0 . 02 MNaOH solution is mixed with 50 mL of 0 . 06 M acetic acid solution, the pH of the resulting solution is_________ ( pKa of acetic acid is 4 . 76 , log 5 = 0 . 70 ) .

Step-by-step solution

When a strong base is added to a weak acid solution, it results in the formation of a salt. Here, acid is present in a limiting reagent and base is present in excess amounts. So, by using the pH formula: p H = p K a + log s a l t a c i d p H = 4 . 46 +   log 0 . 02 × 50 ( 0 . 06 - 0 . 02 ) × 50           p H = 4 . 76 + log ( 0 . 5 ) p H = 4 . 46