AP EAMCET201921 Apr 2019Morning ShiftChemistryIonic EquilibriumActual
The solubility product of a sparingly soluble salt A₂ B is 3.2 10⁻¹¹ . Its solubility in mol L ⁻¹ is
Options
- A4 10⁻⁴
- B2 10⁻⁴
- C6 10⁻⁴
- D3 10⁻⁴
Correct answer
B. 2 10⁻⁴
Step-by-step solution
For the salt of type A₂ B , solubility product (K_ sp )=x^x y^y S^ x+y where, x and y are the number of moles of A and B respectively. S= solubility. Thus, K_ sp =2^2 1^1 S²⁺¹ K_ sp =4 S^3 Given, K_ sp for A₂ B=3.2 10⁻¹¹ array ll & 3.2 10⁻¹¹=4 S^3 or, & S^3= 3.2 4 10⁻¹¹=8 10⁻¹² Thus, & S=2 10⁻⁴ array Hence, option (b) is the correct answer.