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JEE Main20265 April 2026Morning ShiftPhysicsWaves and SoundActual

A transverse wave on a string is described by y = 3 (36t + 0.018x + /4) , where x, y are in cm and t in seconds. The least distance between the two successive crests in the wave is _____ cm. (Nearest integer) ( = 3.14 )

Correct answer

0

Step-by-step solution

The standard equation of a transverse wave is given by y = A ( t + kx + ) Comparing this with the given equation y = 3 (36t + 0.018x + /4) , we get the wave number k = 0.018 cm ⁻¹ . The least distance between two successive crests is the wavelength of the wave. We know that k = 2 = 2 k = 2 3.14 0.018 = 6.28 0.018 = 6280 18 = 348.88 cm Rounding to the nearest integer, we get 349 cm . Answer: 349

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