AP EAMCET2014ChemistryIonic Equilibrium
If the ionic product of Ni ( OH )₂ is 1.9 10⁻¹⁵ , the molar solubility of Ni ( OH )₂ in 1.0 M NaOH is
Options
- A1.9 10⁻¹⁸ M
- B1.9 10⁻¹³ M
- C1.9 10⁻¹⁵ M
- D1.9 10⁻¹⁴ M
Correct answer
C. 1.9 10⁻¹⁵ M
Step-by-step solution
aligned & NaOH CM Na ⁺ + CM OH ⁻ & Ni ( OH )₂ Ni _x²⁺+ x 2 OH ⁻ & K_ sp = [ Ni ²⁺ ] [ OH ⁻ ]^2 & =x(x+C)^2 & aligned =x (x^2+2 C x+C^2 ) or aligned K_ sp & .=x C^2 (neglecting higher powers of x ) x & = K_ sp c ^2 = 1.9 10⁻¹⁵ (1)^2 & =1.9 10⁻¹⁵ M aligned