Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202623 January 2026Evening ShiftPhysicsWork, Power and EnergyActual

A bead P sliding on a frictionless semi-circular string (A C B) and it is at point S at t =0 and at this instant the horizontal component of its velocity is v . Another bead Q of the same mass as P is ejected from point A at t=0 along the horizontal string A B , with the speed v , friction between the beads and the respective strings may be neglected in both cases. Let t_ P and t_ Q be the respective times taken by b

Options

  1. A^ t_ P < t_ Q
  2. B^ t_ P >t_ Q
  3. C^ t_ P =t_ Q
  4. Dt_ P >1.25 t_ Q

Correct answer

A. ^ t_ P < t_ Q

Step-by-step solution

Horizontal displacement of Q is more than P. X_Q > X_P Horizontal component of velocity is same So t_p = x_p v t_Q = x_Q v t_Q > t_p

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All JEE Main PYQs