JEE Main202623 January 2026Evening ShiftPhysicsWork, Power and EnergyActual
A bead P sliding on a frictionless semi-circular string (A C B) and it is at point S at t =0 and at this instant the horizontal component of its velocity is v . Another bead Q of the same mass as P is ejected from point A at t=0 along the horizontal string A B , with the speed v , friction between the beads and the respective strings may be neglected in both cases. Let t_ P and t_ Q be the respective times taken by b
Options
- A^ t_ P < t_ Q
- B^ t_ P >t_ Q
- C^ t_ P =t_ Q
- Dt_ P >1.25 t_ Q
Correct answer
A. ^ t_ P < t_ Q
Step-by-step solution
Horizontal displacement of Q is more than P. X_Q > X_P Horizontal component of velocity is same So t_p = x_p v t_Q = x_Q v t_Q > t_p