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JEE Main 202621 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Morning Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2026 · 21 January · Morning Shift · Physics · Work, Power and Energy

Potential energy ( V ) versus distance ( x ) is given by the graph....

Potential energy (VV) versus distance (xx) is given by the graph. Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low.
Potential energy ( V ) versus distance ( x ) is given by the graph. Rank various regions as per the magnitudes of the

Options

  1. AFCD>FAB>FBC>FDEF_{C D}>F_{A B}>F_{B C}>F_{D E}
  2. BFCD>FDE>FAB>FBCF_{C D}>F_{D E}>F_{A B}>F_{B C}
  3. CFBC>FCD>FDE>FABF_{B C}>F_{C D}>F_{D E}>F_{A B}
  4. DFBC>FAB>FDE>FCDF_{B C}>F_{A B}>F_{D E}>F_{C D}

Correct answer

D. FBC>FAB>FDE>FCDF_{B C}>F_{A B}>F_{D E}>F_{C D}

Step-by-step solution

Force is related to potential energy by F=−dVdxF = -\frac{dV}{dx}.
Magnitude of force ∣F∣=∣dVdx∣|F| = \left|\frac{dV}{dx}\right| = |slope of V-x graph|
From graph coordinates: A(1, 0), B(1.5, 1), C(2, 4), D(4, 4), E(5, 3)
∣FAB∣=1−01.5−1=2|F_{AB}| = \frac{1-0}{1.5-1} = 2
∣FBC∣=4−12−1.5=6|F_{BC}| = \frac{4-1}{2-1.5} = 6
∣FCD∣=4−44−2=0|F_{CD}| = \frac{4-4}{4-2} = 0
∣FDE∣=∣3−4∣5−4=1|F_{DE}| = \frac{|3-4|}{5-4} = 1
Ranking: FBC>FAB>FDE>FCDF_{BC} > F_{AB} > F_{DE} > F_{CD}
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