A block of mass 25 kg is pulled along a horizontal surface by a force at an angle 45^ with the horizontal. The friction coefficient between the block and the surface is 0.25. The displacement of 5 m of the block is:

Step-by-step solution

Block travels with uniform velocity So a =0 ~F 45^ = friction aligned & F 2 = [ mg - F 2 ] & F 2 =0.25 [25 9.8- F 2 ] & 1.25 ~F 2 =61.25 & ~F = 61.25 2 1.25 =49 2 & ~W _ ext = FS 45^ &=49 2 5 1 2 =245 ~J aligned