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JEE Main202522 Jan 2025Morning ShiftPhysicsWork, Power and EnergyActual

A bob of mass m is suspended at a point O by a light string of length l and left to perform vertical motion (circular) as shown in figure. Initially, by applying horizontal velocity v₀ at the point ' A ', the string becomes slack when, the bob reaches at the point ' D '. The ratio of the kinetic energy of the bob at the points B and C is ______ -.

Options

  1. A1
  2. B2
  3. C4
  4. D3

Correct answer

B. 2

Step-by-step solution

aligned & 1 2 mv _ A ^2= 1 2 mv _ B ^2+ mgh & 1 2 ~m (5 ~g )= 1 2 mv _ B ^2+ mg 2 & 5 mg 2 - mg 2 = KE _ B & KE _ B =2 mg & 1 2 mv _ C ^2= 1 2 mv _ D ^2+ mg 2 & KE _ C = 1 2 mg + mg 2 = mg & KE _ B KE _ C =2 aligned

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