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JEE Main 20248 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2024 · 8 April · Morning Shift · Physics · Work, Power and Energy

A stationary particle breaks into two parts of masses m_A and m_B...

A stationary particle breaks into two parts of masses mAandmBm_A and m_B which move with velocities vAandvBv_A and v_B respectively. The ratio of their kinetic energies (KB:KA)\left(K_B: K_A\right) is :

Options

  1. AvB:vAv_B: v_A
  2. BmB:mAm_B: m_A
  3. CmBvB:mAvAm_B v_B: m_A v_A
  4. D1:11: 1

Correct answer

A. vB:vAv_B: v_A

Step-by-step solution

Initial momentum is zero. \begin{aligned} & \text{ Hence }\left|\mathrm{P}_{\mathrm{A}}\right|=\left|\mathrm{P}_{\mathrm{B}}\right| \\ & \Rightarrow \mathrm{m}_{\mathrm{A}} \mathrm{v}_{\mathrm{B}}=\mathrm{m}_{\mathrm{B}} \mathrm{v}_{\mathrm{B}} \\ & \frac{(\mathrm{KE})_{\mathrm{A}}}{(\mathrm{KE})_{\mathrm{B}}}=\frac{\frac{1}{2} \mathrm{ m}_{\mathrm{A}} \mathrm{v}_{\mathrm{A}^2}{\frac{1}{2} \mathrm{ m}_{\mathrm{B}} \mathrm{v}_{\mathrm{B}^2}=\frac{\mathrm{v}_{\mathrm{A}}}{\mathrm{v}_{\mathrm{B}}} \\ & \frac{(\mathrm{KE})_{\mathrm{B}}}{(\mathrm{KE})_{\mathrm{A}}}=\frac{\mathrm{v}_{\mathrm{B}}}{\mathrm{v}_{\mathrm{A}}}\end{aligned}
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