JEE Main 202431 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 31 January
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Work, Power and Energy
JEE Main 2024 · 31 January · Evening Shift · Physics · Work, Power and Energy
A body of mass 2kg begins to move under the action of a time...
A body of mass begins to move under the action of a time dependent force given by \overset{\to}{F} = \left(6t\overset{^}{i} + 6{t}^{2}\overset{^}{j}\right)N. The power developed by the force at the time is given by:
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
Given: \overset{\to}{F} = \left(6t\overset{^}{i} + 6{t}^{2}\overset{^}{j}\right)N
Now, \overset{\to}{F} = m\overset{\to}{a} = \left(6t\overset{^}{i} + 6{t}^{2}\overset{^}{j}\right)
⇒ \overset{\to}{a} = \overset{\to}{F}m = \left(3t\overset{^}{i} + 3{t}^{2}\overset{^}{j}\right)
Hence, velocity \overset{\to}{v} = \mathop{∫}_{0}^{t}\overset{\to}{a}dt = \dfrac{3{t}^{2}}{2}\overset{^}{i} + {t}^{3}\overset{^}{j}
Required power,