An artillery piece of mass M 1 fires a shell of mass M 2 horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is :

Step-by-step solution

As linear momentum will be conserved, p ⇀ 1 = p ⇀ 2 Now, kinetic energy can be written as K E = p 2 2 M . Also p is the same for both masses. We can write, K E ∝ 1 m ⇒ K E 1 K E 2 = p 2 2 M 1 p 2 2 M 2 = M 2 M 1