A solid circular disc of mass 50 kg rolls along a horizontal floor so that its center of mass has a speed of 0 . 4 m s - 1 . The absolute value of work done on the disc to stop it is ______ J .

Step-by-step solution

Using work-energy theorem, we get W = ∆ K E ⇒ W = 0 - 1 2 m v 2 + 1 2 I ω 2 ⇒ W = 0 - 1 2 m v 2 1 + K 2 R 2 = - 1 2 × 50 × 0 . 4 2 1 + 1 2 = - 6 J Absolute work = + 6 J Therefore, required value of W = 6 J