A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60 ° by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against

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A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60 ° by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is : g = 10 m s - 2

Quantrex Academy · Accepted Answer

Correct answer: B. 5 J

Work done against frictional force = μ N × 10 = μ m g cos 60 ° × 10 = 0 . 1 × 5 × 10 = 5 J

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60 ° by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is : g = 10 m s - 2

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