JEE Main202429 Jan 2024Morning ShiftPhysicsWork, Power and EnergyActual
A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of friction between the surfaces is 0 . 4 , then the work done against friction (in J ) is:
Options
- A4200
- B3900
- C4000
- D4500
Correct answer
C. 4000
Step-by-step solution
Given m = 100 kg s = 10 m μ = 0 . 4 The frictional force is given by f = μ m g = 0 . 4 × 100 × 10 = 400 N So, the work done by the force can be calculated as follows: W = f × s = 400 × 10 = 4000 J