Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202429 Jan 2024Morning ShiftPhysicsWork, Power and EnergyActual

A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of friction between the surfaces is 0 . 4 , then the work done against friction (in J ) is:

Options

  1. A4200
  2. B3900
  3. C4000
  4. D4500

Correct answer

C. 4000

Step-by-step solution

Given m = 100 kg s = 10 m μ = 0 . 4 The frictional force is given by f = μ m g = 0 . 4 × 100 × 10 = 400 N So, the work done by the force can be calculated as follows: W = f × s = 400 × 10 = 4000 J

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All JEE Main PYQs