Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202429 Jan 2024Morning ShiftPhysicsWork, Power and EnergyActual

The potential energy function (in J ) of a particle in a region of space is given as U = 2 x 2 + 3 y 3 + 2 z . Here x , y and z are in meter. The magnitude of x - component of force (in N ) acting on the particle at point P ( 1 , 2 , 3 ) m is:

Options

  1. A2
  2. B6
  3. C4
  4. D8

Correct answer

C. 4

Step-by-step solution

Given U = 2 x 2 + 3 y 3 + 2 z The expression for the x - component of the force can be calculated as follows: F x = - ∂ U ∂ x = - 4 x Hence, at the point 1 , 2 , 3 m , the value of the force is given by F x = - 4 × 1 N = 4 N

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All JEE Main PYQs