JEE Main202429 Jan 2024Morning ShiftPhysicsWork, Power and EnergyActual
The potential energy function (in J ) of a particle in a region of space is given as U = 2 x 2 + 3 y 3 + 2 z . Here x , y and z are in meter. The magnitude of x - component of force (in N ) acting on the particle at point P ( 1 , 2 , 3 ) m is:
Options
- A2
- B6
- C4
- D8
Correct answer
C. 4
Step-by-step solution
Given U = 2 x 2 + 3 y 3 + 2 z The expression for the x - component of the force can be calculated as follows: F x = - ∂ U ∂ x = - 4 x Hence, at the point 1 , 2 , 3 m , the value of the force is given by F x = - 4 × 1 N = 4 N