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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2023 · 15 April · Morning Shift · Physics · Work, Power and Energy

A body is released from a height equal to the radius (R) of the...

A body is released from a height equal to the radius (R)\left(R\right) of the earth. The velocity of the body when it strikes the surface of the earth will be: (Given g=g = acceleration due to gravity on the earth.)

Options

  1. A2gR\sqrt{2gR}
  2. BgR\sqrt{gR}
  3. C4gR\sqrt{4gR}
  4. DgR2\sqrt{\dfrac{gR}{2}}

Correct answer

B. gR\sqrt{gR}

Step-by-step solution

Using conservation of mechanical energy,

Ui+Ki=Uf+Kf{U}_{i} + {K}_{i} = {U}_{f} + {K}_{f}

⇒−GMm2R+0=−GMmR+12mv2⇒ - \dfrac{GMm}{2R} + 0 = - \dfrac{GMm}{R} + \dfrac{1}{2}m{v}^{2}

⇒12mv2=GMm2R⇒ \dfrac{1}{2}m{v}^{2} = \dfrac{GMm}{2R}

⇒v=GMR=gR⇒ v = \sqrt{\dfrac{GM}{R}} = \sqrt{gR}

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