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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2023 · 15 April · Morning Shift · Physics · Work, Power and Energy

A block of mass 10kg is moving along x -axis under the action of...

A block of mass 10kg10kg is moving along xx-axis under the action of force F=5xNF = 5xN. The work done by the force in moving the block from x=2mx = 2m to 4m4m will be _______ JJ.

Correct answer

0

Step-by-step solution

Work done is W=∫FdxW = ∫ Fdx

It is given that

F=5xNF = 5xN

So, work done is

W=∫245xdx=5x2224⇒W=5(16−4)2=30JW = {∫}_{2}^{4}5xdx = {\dfrac{5{x}^{2}}{2}}_{2}^{4} ⇒ W = \dfrac{5 ( 16 - 4 )}{2} = 30J

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