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JEE Main 202313 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Evening Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2023 · 13 April · Evening Shift · Physics · Work, Power and Energy

A car accelerates from rest of um s ^ - 1 . The energy spent in...

A car accelerates from rest of ums−1um{s}^{- 1}. The energy spent in this process is EJEJ. The energy required to accelerate the car from ums−1um{s}^{- 1} to 2ums−12um{s}^{- 1} is nEJnEJ. The value of nn is _____.

Correct answer

0

Step-by-step solution

The kinetic energy of a moving particle is given by

E=12mu2...(1)E = \dfrac{1}{2}m{u}^{2} . . . ( 1 )

When the final velocity of the particle becomes twice the initial velocity, the kinetic energy of the particle can be written as

{nE=12m{(2u)2−u2}=12m(3u2)...(2)\begin{cases}nE & = & \dfrac{1}{2}m\left\{( 2u{)}^{2} - {u}^{2}\right\} \\ & = & \dfrac{1}{2}m\left(3{u}^{2}\right) . . . \left(2\right)\end{cases}

Divide equation (2) by equation (1) and solve to calculate the value of nn.

{nEE=12m(3u2)12mu2⇒n=3\begin{cases}\dfrac{nE}{E} & = & \dfrac{\dfrac{1}{2}m\left(3{u}^{2}\right)}{\dfrac{1}{2}m{u}^{2}} \\ & ⇒ & n = 3\end{cases}

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