The momentum of a body is increased by 50 % . The percentage increase in the kinetic energy of the body is_ _ _ _ _ _ _ _ % .

Step-by-step solution

The relation of kinetic energy and momentum is given by K = p 2 2 m The new value of momentum is p ' = 1 . 5 p The new value of kinetic energy is ⇒ K ' = 1 . 5 p 2 2 m = 2 . 25 K Hence, the percentage increase in kinetic energy is K ' - K K × 100 = 2 . 25 K - K K = 125 %