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JEE Main20231 Feb 2023Evening ShiftPhysicsWork, Power and EnergyActual

A force F = ( 5 + 3 y 2 ) acts on a particle in the y -direction, where F is newton and y is in meter. The work done by the force during a displacement from y = 2 m to y = 5 m is ______ J .

Correct answer

0

Step-by-step solution

If an object is moved by certain distance by the application of an external force along the direction of the force, then the force is said to perform some work. Given, the force exerted on the object is F = 5 + 3 y 2 The formula to calculate the work done W by the force in moving the object from a position y 1 to another position y 2 can be written as W =   ∫ y 1 y 2 F d y . . . . . . . . . . . . . . . . . . . . . . . . . . ( 1 ) Substitute the values into equation (1) and solve to calculate the required

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