As per the given figure, two blocks each of mass 250 g are connected to a spring of spring constant 2 N m - 1 . If both are given velocity v in opposite directions, then maximum elongation of the spring is

Step-by-step solution

Let the maximum elongation of the spring be x . Using energy conservation Loss in kinetic energy of both blocks = Gain in spring energy 1 2 m v 2 × 2 = 1 2 k x 2 ⇒ 0 . 25 v 2 = 1 2 × 2 × x 2 ⇒ 1 4 v 2 = 1 2 × 2 × x 2 ∴ x = v 2