A bag of sand of mass 9 . 8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 ms - 1 gets embedded in it, then loss of kinetic energy will be

Step-by-step solution

If the final velocity of the bullet and the bag is v , applying conservation of momentum, m u = m + M v ⇒ 0 . 2 × 10 = 0 . 2 + 9 . 8 v ⇒ v = 0 . 2   m   s - 1 Loss in kinetic energy will be, K i - K f = 1 2 × 0 . 2 × 10 2 - 1 2 × 10 × 0 . 2 2 = 9 . 8   J