A body of mass 0 . 5 kg travels on straight line path with velocity v = 3 x 2 + 4 m s - 1 . The net work done by the force during its displacement from x = 0 to x = 2 m is

Step-by-step solution

Given: v = 3 x 2 + 4 Initial and final velocities are v i = 3 0 2 + 4 = 4   m   s - 1 and v f = 3 2 2 + 4 = 16   m   s - 1 From work-energy theorem, ⇒ Δ K E = 1 2 m v f 2 - v i 2 ⇒ Δ K E = 1 2 × 1 2 16 2 - 4 2 ⇒ Δ K E = W = 60   J