In the given figure, the block of mass m is dropped from the point ' A ' . The expression for kinetic energy of block when it reaches point ' B ' is

Step-by-step solution

Here, gain in kinetic energy = loss in potential energy Now loss in potential energy of particle in falling from height y to y 0 is m g y - y 0 . So, Δ K E = K - 0 = - m g y - y 0 - m g y Thus, kinetic energy at point B is K = m g y 0